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Theory and Application of a case of cavity

There are two types of resonant cavity axis. (1) a / 4 (quarter wavelength) shorter line resonator. Both ends of the short-circuit coaxial line when its length L satisfies the condition: L = n ÷ 1: (p-£.) An ancient. J (17) to constitute a resonant cavity. Type applications. Is the free space wavelength, e, is a coaxial cavity (between the two lines) relative permeability of the medium and the relative dielectric constant. L 0 a / 4, the inductive input impedance of coaxial line. In the UHF tuner, with the length close to the x / 4 wire,p90x workout calendar, instead of the terminal short circuit inductance, and the other - Jing is connected with a variable capacitor, this is equivalent to an LC resonator tuned Kui Road, with the input of the tuner High-level loop and double-tuned circuit level. (2) / 2 (half wavelength), open line resonator. Open a terminal wire, when its length L in / 4 a / 2, the conductor of the input impedance is inductive. Use of the equivalent inductance and capacitance form an additional group of open cavity harmonic coaxial line. The structure is placed at the center of a metal chamber X / 4 ~ X / 2 long wires, wire both ends open, one side then the resonant capacitor C, can be composed of LC tuned circuit, used in the UHF tuner's local oscillator . How to encourage and sprinkle cavity output, that is, how coupled sets it? Methods are commonly used in the coupling capacitor coupled Taiwan Taiwan, inductively coupled sets of coupling units coupled ring and Taiwan, and other openings. Figure 2 (Lower Dir 24_ JIANGHAN literature of 224 buildings (consolidated version) 1091 No. 6 - _-_____l_ Ⅱ 11'r |! '-TI-_-● ● - Since d - __ ●'. _1_t. - a -!, Japan E! jE_ - 1r1 {Et - Day _l-_ at ___ ● H''±!,','|-' r-! 1 - ● ● _1_r-__-________ ● __ a rest, nothing more than the real axis root locus, as shown in Figure 7 (a) below. Another example is when A (s) a (s +1) (s +4) = s +5 s +4, B (s ) = (s +2) (s +3) a s. +5 s +6, also for a = b, or.o a.., R a.., the root locus shown in Figure 7 (b) shows 6. When A (s) = (s-F2) (s +6) = s-F8s +12, B (s) = (s +4) (s + Super

= s-Fl2s +3 s, the. = a 5, but R a = T = _l non-real axis root locus, in fact, the root axis rail as shown in Figure 7 (c) below = no real solution, no conclusion can be seen when J.T (o, 2) type of second-order system through the intersection of all the root locus (J a - a / 2) parallel to the axis of straight lines and boo the real axis. '2. T (1,2)-type Z-order system of all root locus in (I9) holds the real axis under the conditions of a bo for the park and in the heart of the park, otherwise the real axis. 3.T (2,2)-type root locus of all second-order system in (24) under the conditions established for the real axis and Garden special circumstances] Park